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-8+49x^2=28
We move all terms to the left:
-8+49x^2-(28)=0
We add all the numbers together, and all the variables
49x^2-36=0
a = 49; b = 0; c = -36;
Δ = b2-4ac
Δ = 02-4·49·(-36)
Δ = 7056
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{7056}=84$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-84}{2*49}=\frac{-84}{98} =-6/7 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+84}{2*49}=\frac{84}{98} =6/7 $
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